Need help with these...or more like I forget algebra.
$\displaystyle 4y^2 - x^2 = 1$
$\displaystyle 4y^2 + x^2 = 1$
Thanks.
$\displaystyle 4y^2 - x^2 = 1$
this is a hyperbola with the foci on the y axis
you can ussually tell by the - sign in between
the general equation is:
$\displaystyle \frac{y^2}{a^2} - \frac{x^2}{b^2} = 1$
where $\displaystyle b^2 = c^2 - a^2$
$\displaystyle c > a, c > b$
$\displaystyle 4y^2+ x^2 = 1$
this is an ellipse
the general equation is:
$\displaystyle \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$
where $\displaystyle b^2 = a^2 - c^2$
$\displaystyle a > b, a > c$