I have my notes from class and there is an example in the book but I am not sure what I am doing. The point P(4,28) lies on the curve Y = x^2+x+8. If Q is the point (x,x^2+x+8), find the slope of the secant line PQ for the following values of x.

If x = 4.01, then the slope of PQ is:

and if x = 4.01, the slope of PQ is:

and if x = 3.9, the slpe of PQ is:

and if x = 3.99, the slope of PQ is:

Based on the above results, guess the slpoe of the tangent line to the curve at P(4,28).

If you could give me a hint so I can finish this one and do the other problems I would appreciate it

Thank you again!!!!!!!!

Keith Stevens