fraction decomposition..??

Us partial fraction decomposition to decompose the given expression: (2x^2+1)/(x^3+2x^2+x)


(2x^2+1)/(x^3+2x^2+x)
= (2x^2+1)/[x(x^2+2x+1)
= (A/x) + (B/(x+1)) + (C/(x+1))
= (2x^2+1)/(x^3+2x^2+x) * (x^3+2x^2+x) = [(A/x) + (B/(x+1)) + (C/(x+1))]*(x^3+2x^2+x)
= 2x^2+1 = A(x^2+1) + B/(x^2+x) + C/(x^2+x)
= 2x^2+1 = A(x^2+1) + (B+C)(x^2+x)

And that's as far as I got. don't know where to go from there..?

Thank you!

Quote:

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Originally Posted by GreenTea1mochi

(2x^2+1)/(x^3+2x^2+x)

I got up to 2x^2+1 = A(x^2+1) + (B+C)(x^2+x) but don't know where to go from there..?

Thank you!

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First you could tell us how you got to where you are, and expressing the question clearly would do no harm either.

I presume that you are required to find the partial fraction decomposition of:



First factorise the denominator as much as you can:



Now you need to find and such that:



CB

Quote:

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Originally Posted by GreenTea1mochi

.....help please?

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Don't bump.

If you are having difficulties explain what they are, give us a clue.

CB