If I solve a quadratic equation and I get the values for x as
x=1.788887778 and x=1.11382983
what would they usually round to?
is this allowed?
The values of x that you find are only approximative. The goal of solve a quadratic equation is to find two, one (equals) or zero (in , of course).
Don't try to put they back to the equation, it doesn't work if the values aren't integers.
FYI: Non-integral values can be checked. But you'd have to work exactly. For instance, 3x^2 - 2x - 6 = 0 solves as:
To check one of the solutions:
...and so forth.
Apparently, your original equation was , since you put x= -1.1 (after saying that x= 1.11 was a solution!) into that.
By the quadratic formula, . and are the correct roots.
is about 8.72 so x is approximately 1.79 or -1.14. I've reduced those to two decimal places because you gave two decimal places as your first answer. What reason do you have to further reduce to 1.8 and -1.1?