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Math Help - Polar Equation to Rectangular Form

  1. #1
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    Polar Equation to Rectangular Form

    Hello, I was just wondering if anyone could possibly help me convert this into rectangular form.

    To make it simpler (t) = theta.

    r(1+cos(t))=2

    So far I have distributed the r through the equation and squared both sides:

    (r+rcos(t))^2 = 2^2
    r^2+2r^2cos(t)+r^2cos^2(t)=4 : From here I took out the r^2
    r^2(1+2cos(t)+cos^2(t)=4 : Here is where I get stuck.

    I'm not sure if I'm taking the right path or not, any help would be appreciated.

    Thanks!
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  2. #2
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    Quote Originally Posted by McFroggerton View Post
    Hello, I was just wondering if anyone could possibly help me convert this into rectangular form.

    To make it simpler (t) = theta.

    r(1+cos(t))=2

    So far I have distributed the r through the equation and squared both sides:

    (r+rcos(t))^2 = 2^2
    r^2+2r^2cos(t)+r^2cos^2(t)=4 : From here I took out the r^2
    r^2(1+2cos(t)+cos^2(t)=4 : Here is where I get stuck.

    I'm not sure if I'm taking the right path or not, any help would be appreciated.

    Thanks!
    r + r\cos{\theta} = 2

    \sqrt{x^2+y^2} + x = 2
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