solve the logarithmic equation w/o calculator.

$\displaystyle ln (x+2)=ln e^{ln2}-ln x$

So I got...

$\displaystyle (x+2)=e^{ln2}-x$ [Logs are 1to1]

$\displaystyle 2x+2=e^{ln2}$

so i don't know what to do with the $\displaystyle e^{ln2}$ w/o calculator.