# Math Help - logarithmic equation

1. ## logarithmic equation

solve the logarithmic equation w/o calculator.

$ln (x+2)=ln e^{ln2}-ln x$
So I got...
$(x+2)=e^{ln2}-x$ [Logs are 1to1]
$2x+2=e^{ln2}$
so i don't know what to do with the $e^{ln2}$ w/o calculator.

2. Originally Posted by windir
solve the logarithmic equation w/o calculator.

$ln (x+2)=ln e^{ln2}-ln x$
So I got...
$(x+2)=e^{ln2}-x$ [Logs are 1to1]
$2x+2=e^{ln2}$
so i don't know what to do with the $e^{ln2}$ w/o calculator.
$ln (x+2)=ln e^{ln2}-ln x$

$\ln(x+2)=\ln\frac{e^{\ln(2)}}{x}$

$x+2=\frac{e^{\ln(2)}}{x}$

$x+2=\frac{2}{x}$

Has no real roots...

3. just saw the final part not the work leading to it.

4. Thanks!