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Thread: logarithmic equation

  1. November 7th 2009, 07:02 PM #1
    windir
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    logarithmic equation

    solve the logarithmic equation w/o calculator.

    ln (x+2)=ln e^{ln2}-ln x
    So I got...
    (x+2)=e^{ln2}-x [Logs are 1to1]
    2x+2=e^{ln2}
    so i don't know what to do with the e^{ln2} w/o calculator.
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  2. November 7th 2009, 07:17 PM #2
    VonNemo19
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    Quote Originally Posted by windir View Post
    solve the logarithmic equation w/o calculator.

    ln (x+2)=ln e^{ln2}-ln x
    So I got...
    (x+2)=e^{ln2}-x [Logs are 1to1]
    2x+2=e^{ln2}
    so i don't know what to do with the e^{ln2} w/o calculator.
    ln (x+2)=ln e^{ln2}-ln x

    \ln(x+2)=\ln\frac{e^{\ln(2)}}{x}

    x+2=\frac{e^{\ln(2)}}{x}

    x+2=\frac{2}{x}

    Has no real roots...
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  3. November 7th 2009, 07:19 PM #3
    11rdc11
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    just saw the final part not the work leading to it.
    Last edited by 11rdc11; November 7th 2009 at 07:31 PM. Reason: didn't check orginal posters work carefully
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  4. November 7th 2009, 08:24 PM #4
    windir
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    Thanks!
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