logarithmic equation

• November 7th 2009, 08:02 PM
windir
logarithmic equation
solve the logarithmic equation w/o calculator.

$ln (x+2)=ln e^{ln2}-ln x$
So I got...
$(x+2)=e^{ln2}-x$ [Logs are 1to1]
$2x+2=e^{ln2}$
so i don't know what to do with the $e^{ln2}$ w/o calculator.
• November 7th 2009, 08:17 PM
VonNemo19
Quote:

Originally Posted by windir
solve the logarithmic equation w/o calculator.

$ln (x+2)=ln e^{ln2}-ln x$
So I got...
$(x+2)=e^{ln2}-x$ [Logs are 1to1]
$2x+2=e^{ln2}$
so i don't know what to do with the $e^{ln2}$ w/o calculator.

$ln (x+2)=ln e^{ln2}-ln x$

$\ln(x+2)=\ln\frac{e^{\ln(2)}}{x}$

$x+2=\frac{e^{\ln(2)}}{x}$

$x+2=\frac{2}{x}$

Has no real roots...
• November 7th 2009, 08:19 PM
11rdc11
just saw the final part not the work leading to it.
• November 7th 2009, 09:24 PM
windir
Thanks!