Complex number problem

**ggeek101** · November 5th 2009, 05:14 PM

"Let z be a complex number and z (w/ a bar over it) be its conjugate. What are the four values of z for which zz(bar) and z^2 + z(bar)^2 = 6 ?"

I can't seem to a get an answer...I just did a lot of work and didn't get anything. I simplified it down to z^4 + 25 / z^2 = 6 and -z(bar) +6z(bar)^2 = 25, but that's all.

**artvandalay11** · November 5th 2009, 05:30 PM

Originally Posted by ggeek101

"Let z be a complex number and z (w/ a bar over it) be its conjugate. What are the four values of z for which zz(bar) and z^2 + z(bar)^2 = 6 ?"

I can't seem to a get an answer...I just did a lot of work and didn't get anything. I simplified it down to z^4 + 25 / z^2 = 6 and -z(bar) +6z(bar)^2 = 25, but that's all.

$z=a+bi$
$\bar{z}=a-bi$

$z^2=a^2+2abi-b^2$
$\bar{z} ^2=a^2-2abi-b^2$

$z^2+\bar{z}^2=2a^2-2b^2=6$

$z\bar{z}=a^2+b^2=6$

So solve $a^2-b^2=3$ and $a^2+b^2=6$

**ggeek101** · November 5th 2009, 05:51 PM

Wow, I over thought this problem. I like your approach. Thanks!

**artvandalay11** · November 5th 2009, 05:53 PM

no problemo.... i took it further and i believe the answers are not pretty, just so you're aware

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