I need to find the inverse of the equation: f(x)=(2x+1)/(x+3) Please help me.
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Originally Posted by takuto I need to find the inverse of the equation: f(x)=(2x+1)/(x+3) Please help me. $\displaystyle y = \frac{2x+1}{x+3} $ swap x and y ... $\displaystyle x = \frac{2y+1}{y+3}$ solve for y ... $\displaystyle xy+3x = 2y+1$ $\displaystyle xy-2y = 1-3x$ $\displaystyle y(x-2) = 1-3x$ $\displaystyle y = \frac{1-3x}{x-2} = f^{-1}(x)$
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