The title "Another one on ellipse" is the clue. Without playing yet, the locus of that particular point is an ellipse.

After some playing with the line segment and the two coordinate axes, yes, the locus is an ellipse.

If the line segment is vertical, the point is 4 units from the x-axis.

Sliding the line segment to the left, when it is horizontal, the point is 8 units from the y-axis.

Then, sliding the line segment down, when it is vertical again, the point is 4 units from the x-axis.

Then, sliding the line segment to the right, when it is horizontal again, the point is 8 units from the y-axis.

Then, sliding the line segment up, when it is vertical, it is in the same position before, the point is 4 units from the x-axis.

So, the ellipse is "horizontal" or the major axis is along the x-axis.

major axis = 8+8 = 16 units long.

minor axis = 4+4 = 8 units high.

A standard equation of an ellipse centered at the origin (0,0), whose major axis, 2a, is along the x-axis, and whose minor axis, 2b, is then along the y-axis is

(x^2)/(a^2) +(y^2)/(b^2) = 1

Therefore the equation of the locus of that particular point is:

(x^2)/(8^2) +(y^2)/(4^2) = 1

(x^2)/64 +(y^2)/16 = 1 -----------------answer.