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Math Help - Slope of a Secant

  1. #1
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    Slope of a Secant

    There are several of these problems-all of which are very closely related. If someone could please get me started it would help me out alot. The problems are as follows:...


    The point P(5,37) lies on the curve y=x^2+x+7. If Q is the point (x, x^2 + x + 7 ), find the slope of the secant line PQ for the following values of x:

    If x=5.1, the slope of PQ is:



    Ohh Yea one other thing the formula for the slope of secant line is:

    m_{PQ} = \frac { y_{Q} - y_{P}}{x_{Q} - x_{P}}

    Thanks!
    Last edited by qbkr21; February 5th 2007 at 01:39 PM.
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  2. #2
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    Hello, qbkr21!

    This problem is straight-forward ... and you know the Slope Formula.
    So exactly where is your difficulty?

    And I assume there is a typo in your problem . . .


    The point P(5, 37) lies on the curve y\:=\:x^2+x+7.
    Find the slope of the secant line PQ for x = 5.1

    When x = 5.1\!:\;\;y \:=\:5.1^2 + 5.1 + 7 \:=\:38.11
    . . Hence, point Q is (5,1,\,38.11)

    Can you find the slope of PQ now?
    . . P(5,37),\;Q(5.1,\,38.11)

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  3. #3
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    Soroban I am very sorry for the typo
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  4. #4
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    Ok, Now I see. So therefore and with respect to your setup the answer would be

    \frac{38.11-37}{5.1-5} = 11.1

    Thanks!
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