find the range of values for k for which the function $\displaystyle \frac{x^2-1}{(x-2)(x+k)}$ where x is real, takes all real values. I don't know how to start. Any pointers? Thanks
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The question asks you for what values of X, would F(x) exist. Or what values of X would F(x) not exist. Hint: C/0 doesn't exist (where C is an arbitrary constant).
so x cannot be 2 or -k. i dont know what else the answer is $\displaystyle |k|\leq 1$
Sorry, I misread the question. I thought you were supposed to find values for x instead of k. So same as idea as before. We know that k cannot be -x and we also know that x can't be 2. Therefore, k cannot be -2 (I think).
ok got that, but how to continue confuses me
What part are you confused about? You know that k can't be -x, and when x = 2, k can't be -2.
yes, i meant how to find the values of k other than that it isn't -2.
The domain for is k $\displaystyle (- \infty, -x)\cup(-x, \infty)$ The domain of x is $\displaystyle (- \infty, -2)\cup(-2, \infty)$
Last edited by statmajor; Nov 4th 2009 at 07:34 PM.
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