Hi, I'm kinda lost where to start this problem. Any help would be great. Thanks.
Solve for x:
$\displaystyle 3x^\frac{3}{2} -2x=0$
1. It is not a polynomial. Polynomials only have positive integer powers.
2. Factorise and solve using the Null Factor Law.
$\displaystyle 3x^{\frac{3}{2}} - 2x = 0$
$\displaystyle x\left(3x^{\frac{1}{2}} - 2\right) = 0$
$\displaystyle x = 0$ or $\displaystyle 3x^{\frac{1}{2}} - 2 = 0$.
Can you go from here?