The problem asks to solve the following expression for y in terms of x if x is not equal to zero and y is not equal to zero:

1/X + 1/XY =y

THanks :)

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- Oct 17th 2005, 04:41 PMtrinhPre-Calc HELP ASAP! PLEASE!!
The problem asks to solve the following expression for y in terms of x if x is not equal to zero and y is not equal to zero:

1/X + 1/XY =y

THanks :) - Oct 18th 2005, 01:17 AMticbol
From 1/x +1/(xy) = y, you want to find y in terms of x only.

Okay.

You then have to isolate the y's, and do anything to have "y" only on one side of the equation. That will get x on the other side.

1/x +1/(xy) = y

Clear the fractions, multiply both sides by xy,

y +1 = x*y^2

Umm, we are getting a quadratic equation in "y",

0 = x*y^2 -y -1

Or,

x*y^2 -y -1 = 0

Use the Quadratic Formula,

y = {-(-1) +,-sqrt[(-1)^2 -4(x)(-1)]} / (2*x)

y = {1 +,-sqrt[1 +4x]} / 2x ------------------****

That means,

y = [1 +sqrt(1+4x)]/(2x)

or, y = [1 -sqrt(1+4x)]/(2x)