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Math Help - Help with polynomial equations

  1. #1
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    Help with polynomial equations

    16. Determine algebraically where the cubic polynomial function that has zeros at 2,3, and -5 and passes through the point (4,36) has a value of 120.

    So I did (x-2)(x-3)(x+5)=y (4,36) SUB
    (4-2)(4-3)(4+9)=36
    (2)(1)(9)=36
    18a/18=36/18=2

    so 2(x-2)(x-3)(x+5)=120???.. im not sure what to do next.
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  2. #2
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    Quote Originally Posted by Skoz View Post
    16. Determine algebraically where the cubic polynomial function that has zeros at 2,3, and -5 and passes through the point (4,36) has a value of 120.

    So I did (x-2)(x-3)(x+5)=y (4,36) SUB
    (4-2)(4-3)(4+9)=36
    (2)(1)(9)=36
    18a/18=36/18=2

    so 2(x-2)(x-3)(x+5)=120???.. im not sure what to do next.
    (x-2)(x-3)(x+5) = 60

    expand the left side, set the resulting cubic = 0, then solve for x
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