**The question is, Solve the equation!** Attachment 13603 *I think I have solved the first part...*
x = 8

y = -1

z = 3

This is is only one of the solutions: if you write down your augmented matrix, you get after simplifying it (by Gauss's method, say): $\displaystyle \left(\begin{array}{cccc}1&1&\!\!\!\!-1&4\\0&\!\!\!\!-3&1&6\\0&\!\!\!\!-9&1&18\end{array}\right)$
As the third row is clearly a scalar multiple of the 2nd one it will vanish in the next step, and the general solution is

$\displaystyle 2nd\,\;row\;:\;\;-3y+z=6\Longrightarrow y=-2+\frac{1}{3}z$

$\displaystyle 1st\,\;row\;:\;\;z-2+\frac{1}{3}z-z=4 \Longrightarrow x=6+\frac{2}{3}z$

As you can see, we wrote x,y as functions of z. Now just write $\displaystyle z=t$ and we're done.

This solution means: for ANY choice of the parameter t, you plug in this choice above for z and thus for x,y and you'll get a solution.

Tonio[/color]

**But then they say that the answer has to be written as;** Attachment 13604 Where *a,b,c,d,e,f,g,h* have to be itegers.
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I have absolutely no idea how to solve this problem. Please help! What is... **a**=? **b**=?

**c**=?

**d**=?

**e**=?

**f**=?

**g**=?

**h**=?

Thanks!