Hello, Can someone please help me with this problem? Problem: csc(pi/2 - u) = sec u I understand that csc = 1/sin how do I factor ----- 1/sin(pi/2-u) That's where I'm basically stuck. Let me know, thanks!
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Originally Posted by l flipboi l Hello, Can someone please help me with this problem? Problem: csc(pi/2 - u) = sec u I understand that csc = 1/sin how do I factor ----- 1/sin(pi/2-u) That's where I'm basically stuck. Let me know, thanks! For and
Last edited by e^(i*pi); Oct 31st 2009 at 01:30 PM. Reason: typo
Originally Posted by l flipboi l Hello, Can someone please help me with this problem? Problem: csc(pi/2 - u) = sec u I understand that csc = 1/sin how do I factor ----- 1/sin(pi/2-u) That's where I'm basically stuck. Let me know, thanks! continue ...
So the law of distributing fractions is: a/b (c+d) = a / (bc+bd) ?
Originally Posted by l flipboi l So the law of distributing fractions is: a/b (c+d) = a / (bc+bd) ? don't complicate things ... just evaluate/simplify the expression and finish the proof.
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