Hi i've got this question of definite integration (1/5x-6) dx where x=0 from x=1

Ive got [1/5 log (5x+6)] x=1 x=0

= [1/5 log (5+6)] - [1/5log(0+6)]

= 0.208 - 0.1556

=0.0526

Am i supposed to have it as a decimal.. and how do i avoid using a decimal cos my friend got an answer of -log(6)/5

And sorry not sure how to do the integration sign on the computer haha