2.5 per minute, try to work out the details, if you cant figure it out post again
Can you help with this ? Thanks.
A ship's hull was punctured and filled with water before being sealed off. A pump removed water at a steady rate of 5 gallons per minute, but after 75% of the water was removed, the pump slowed. If the water was removed at an average rate of 4 gallons per minute, at what rate was the remaining 25% of the water removed ?
Suppose the water was removed at 5 gallons per minute for minutes. Then where V is the volume of the hull. Suppose further that the pump ran for minutes at r gallons per minute. Then .
Divding the first equation by the second, so .
Then entire volume, V, was emptied in time so the rate was .
But so .
That is, .
Solve that for r.