Hi, I have the problem:
'Find the equation of the tangent to the curve with equation at the point where .'
I'm sure you'd have to use synthetic division (polynomials) at some point but I am not sure.
Many thanks.
Nope, you just have to differentiate the function.
edit: I didn't see as a point.
First get the y co-ordinate at the point where
to give the ordered pair (1,-8)
The gradient, m, is therefore -5.
Use the equation of a straight line and the ordered pair above to get the equation.