Graph: y=f(x)=-x2+3x. Give the coordinates of the vertex, the x-intercepts (if they exist), the y-intercept, the domain, range, max/min value, and the equation of the axis of symmetry.
vertex
x-int.
y-int.
domain
range
max/min
axis of symmetry
Graph: y=f(x)=-x2+3x. Give the coordinates of the vertex, the x-intercepts (if they exist), the y-intercept, the domain, range, max/min value, and the equation of the axis of symmetry.
vertex
x-int.
y-int.
domain
range
max/min
axis of symmetry
Hi Jluse7,
You need to translate your functional notation into vertex form. The graph will be a parabola opening downward.
Complete the square:
This tells you that the vertex of your parabola is at
Set f(x) = 0 to find your x intercepts. Use your original function.
Notice, since x = 0, f(0) = 0, thus the y-intercept is 0.
The domain will be all real numbers. There are no restrictions on x.
The range will be
The maximum value will occur at the vertex where .
There is no minimum.
The axis of symmetry is . This is a vertical line which passes through the vertex.