# Thread: Forming a polynomial function

1. ## Forming a polynomial function

Hey i'm a newbie, and I need help.

I've been absent from school for 5 days and I'm trying really hard to catch up as fast as I can. So the questions this: I'm given a graph with the points (0,0), (0,1), and (0,2) on it with 3 turns, and it says to construct a polynomial function that might have given this graph.
I'm completely lost, and for all I know the answer is staring me in the face. Help a sad teen who's failing Pre-Cal?
Thanks!

2. Originally Posted by indieskid
Hey i'm a newbie, and I need help.

I've been absent from school for 5 days and I'm trying really hard to catch up as fast as I can. So the questions this: I'm given a graph with the points (0,0), (0,1), and (0,2) on it with 3 turns, and it says to construct a polynomial function that might have given this graph.
I'm completely lost, and for all I know the answer is staring me in the face. Help a sad teen who's failing Pre-Cal?
Thanks!
This cannot be a function of y in terms of x because it fails the vertical line test. If you are trying to graph x in terms of y then begin by considering the degree, is it going to be odd or even, then a general form, such as for example, $x = ay^3 + by^2 + cy + d$ if a degree three, then plug in all the points.

I suspect that you are reading the points incorrectly, so it's actually (0,0) (1,0) and (2,0). If these are the points, then use a factor for each zero.
$p(x) = x (x-1) (x-2)$

I hope this helps. good luck!

3. thank youuu xD like i said...failing =p

Thanks again!