i need help
find the real root of the equation z^3 + z + 10=0 given that one root is 1-2i
since 1-2i is a root its complex conjugate 1+2i is also a root
so far i know the sum of the roots is -1
Well, it is:
$\displaystyle (z^3+ 2^3)+ (z+ 2)= 0$ actually.
Apart from that, I take advantage of the fact that 10 = 2*2*2 + 2.
If this is what you asked about?
It does not satisfy the second, because it is not a solution, I guess?
The quadratic one has complex roots. I think. :?
deadmotor, you said the 2 roots are 1-2i and 1+2i because they are pair conjugate, but notice the equation z^3 + z + 10 = 0, sum of roots is zero.
if a, b, and c are the roots, then a + b + c = 0,
a + ( 1 + 2i) + (1 - 2i) = 0, surely you know the third root, right? which is a . . . why not evaluate it?
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It can be factored by grouping,
z^3 + z + 10 = 0,
z^3 + 2z^2 - 2z^2 - 4z + 4z + z + 10 = 0,
z^2(z + 2) - 2z(z + 2) + 5(z + 2) = 0,
(z + 2)(z^2 - 2z + 5) = 0.
surely you know how to use the quadratic formula to find the rest of the roots . . .
Another possibility: if 1 + 2i and 1 - 2i are roots then
z - (1 + 2i) and z - (1 - 2i) are factors
So (z-1-2i)(z-1+2i) is a factor
Simply this and you will get a quadratic. then you need one more factor, which should now be obvious (there are not many choices now that you have the 2nd power of z).
From there you should get the third root.