# Math Help - Need help with this one

1. ## Need help with this one

Find all zeros of the function and write the polynomial as a product of linear factors.

F(x)=x^3+2x^2-3X-10

2. you see,if we put x= 2 then f(x)=0
therefore (x-2) is a factor of f(x)

now divide $x^3+2x^2-3X-10$ by (x-2) to get other factors
if stuck check spoiler
Spoiler:

$x^3+2x^2-3X-10 = (x-2)(x^2+4x+5)$
solving $(x^2+4x+5)$ using $\frac {-b \pm \sqrt{b^2-4ac}}{2a}$
we get x = $(-2\pm i)$
$\therefore x^3+2x^2-3X-10 = (x-2)(x+2+i)(x+2-i)$