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Math Help - Cant find answer, too many variables

  1. #1
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    Cant find answer, too many variables

    How to calculated x1, x2 or x2/x1? When:

    Time 1 Time 2
    x/y = 0.9004 0.9141
    x/z = 1.5015 1.5026
    y/z = 1.6676 1.6438
    x/c = 137.9053 137.9011
    y/c = 153.1600 150.8600
    z/c = 91.8450 91.7750
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  2. #2
    Super Member craig's Avatar
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    Quote Originally Posted by raimundas View Post
    How to calculated x1, x2 or x2/x1? When:

    Time 1 Time 2
    x/y = 0.9004 0.9141
    x/z = 1.5015 1.5026
    y/z = 1.6676 1.6438
    x/c = 137.9053 137.9011
    y/c = 153.1600 150.8600
    z/c = 91.8450 91.7750
    From what I can see you have 4 variables, x y z c and 6 equations, how is this too many variables?
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  3. #3
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    Quote Originally Posted by raimundas View Post
    How to calculated x1, x2 or x2/x1? When:

    Time 1 Time 2
    x/y = 0.9004 0.9141
    x/z = 1.5015 1.5026
    y/z = 1.6676 1.6438
    x/c = 137.9053 137.9011
    y/c = 153.1600 150.8600
    z/c = 91.8450 91.7750
    Actually, your problem is not that there are "two many variables" in the equations but that the ones you want are NOT in the equations!

    You are asking for values of x1 and x2 but there no x1, x2 in the equations. What is the relation between x1, x2 and x, y, z, c?
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  4. #4
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    Hello, raimundas!

    How to calculate x_1,\:x_2,\:\text{ or }\:\frac{x_2}{x_1}

    When:

    , \begin{array}{c||c|c|}\hline<br />
& \;\text{time 1}\: & \;\text{time 2}\: \\ \hline \hline \\[-4mm]<br /> <br />
\dfrac{x}{y} & 0.9004 & 0.9141 \\ \\[-4mm] \hline \\[-4mm]<br />
\dfrac{x}{z} & 1.5015 & 1.5026 \\ \\[-4mm] \hline \\[-4mm]<br />
\dfrac{y}{z} & 1.6676 & 1.6438 \\ \\[-4mm] \hline \\[-4mm]<br />
\dfrac{x}{c} & 137.9053 & 137.9011 \end{array}
    - \begin{array}{c||c|c|}\hline \\[-4mm]<br />
\dfrac{y}{c} & 153.1600 & 150.8600 \\ \\[-4mm] \hline \\[-4mm]<br />
\dfrac{z}{c} & 91.8450 & 91.7750 \\ \\[-4mm] \hline<br />
\end{array}

    HallsofIvy already pointed out the unrelated variables.

    What does "time 1" and "time 2" represent?
    Are we expected to solve two systems of equations?

    It all may clear up if you post the original problem.

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  5. #5
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    Ok. The original problem, im writting bachelor about forex market trade.
    And geting difficult to solve which curency in pairs is strongest and witch is weakest.
    EUR = xGBP = yUSD = zJPY = c

    From the chart it is obviuos that GBP moved down a lot (got weaker in relation to the other currencies), but how to measure the drop in some index. And how to measure which curency's strength moved up (in realation to the oher curencies)?
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