Find the vertical asymptotes of the rational function. H(x)= 3x^2 / (x-7)(x-8) Thanks
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$\displaystyle x \neq 7,8$ therefore vertical asymptotes are $\displaystyle x= 7$ and $\displaystyle x=8$
Originally Posted by relichunter09 Find the vertical asymptotes of the rational function. H(x)= 3x^2 / (x-7)(x-8) Thanks The vertical asymptotes are generally were the function isn't defined, in your case the function is not defined when the denominator is equal to zero. i.e $\displaystyle (x-7)(x-8)=0$ $\displaystyle x=7$ $\displaystyle x=8$ Those are your two vertical asymptotes.
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