Hello,
please help me,
Show that the right circular cone of least curved surface and given volume has an altitude equal to 2^(1/2) time the radius of the base?
[1] Volume of the cone
[2] Area of the curved surface.
Solve [1] for r and plug in this term into [2]:
Now differentiate a wrt h (V is a constant!). You'll get:
Solve a'(h) = 0 for h. This is obviously only possible if
Solve for h. Substitute V by the term of [1] and solve for h again. You'll get
Remark: Especially the differentiation of a is really horrible. So I hope for you that someone knows a simpler, shorter way to solve the question.