# Math Help - A limit question that shouldn't be as hard as it seems to me

1. ## A limit question that shouldn't be as hard as it seems to me

((sqrt[1+2x] - sqrt[1+3x]) / x+2x^2) where x is greater than 0

I know/think the easiest thing would be to get rid of the fraction first, but can't for some reason. Thanks

2. Originally Posted by gixxer998
((sqrt[1+2x] - sqrt[1+3x]) / x+2x^2) where x is greater than 0

I know/think the easiest thing would be to get rid of the fraction first, but can't for some reason. Thanks
Multiply the numerator and denominator by $\sqrt{1 + 2x} + \sqrt{1 + 3x}$, simplify the numerator, cancel the factor common to numerator and denominator and then take the limit.