# Geometry: Plotting a line

• Oct 18th 2009, 02:35 AM
zyx.gar
Geometry: Plotting a line
Maybe be a simple question for you but I'm new to this. I have to plot a line on a graph, It's fine when the line crosses over the x and y axis but after that is where I get stumped.

2x + 5y = 8

x axis -- y=0
2x + 5(0) = 8
2x + 0 = 8
x = 4

y axis -- x=0
2(0) + 5y = 8
0 + 5y = 8
5y = 8
y = 8/5

Have I done that right and does that mean the points are x(0,4) y(8,5)
Do I go up 8 on the y and come out 5 on the x?

Thanks for any help.
• Oct 18th 2009, 02:43 AM
Quote:

Originally Posted by zyx.gar
Maybe be a simple question for you but I'm new to this. I have to plot a line on a graph, It's fine when the line crosses over the x and y axis but after that is where I get stumped.

2x + 5y = 8

x axis -- y=0
2x + 5(0) = 8
2x + 0 = 8
x = 4

y axis -- x=0
2(0) + 5y = 8
0 + 5y = 8
5y = 8
y = 8/5 this is a fraction

Have I done that right and does that mean the points are x(0,4) y(8,5)
Do I go up 8 on the y and come out 5 on the x? you are just making things complicated for yourself

Thanks for any help.

HI

This line will pass through these 2 points .. (4,0) and (0, 8/5)

8/5 = 1.6

Then ur job is simple , just get a ruler and a pensil to connect the 2 points .
• Oct 18th 2009, 03:56 AM
aidan
Quote:

Originally Posted by zyx.gar
Maybe be a simple question for you but I'm new to this. I have to plot a line on a graph, It's fine when the line crosses over the x and y axis but after that is where I get stumped.

2x + 5y = 8

ALONG THE x axis --
y=0 ... x = 4

ALONG THE y axis --
x=0 ... y = 8/5

Plot the first point (4,0) on the x axis;
plot the second point (0, 1.6) on the y axis;
drawn the line connecting the two points & extend the line.
• Oct 18th 2009, 06:43 PM
pacman
equation: 2x + 5y = 8