Thread: first expression of the second

Hello,

Can someone please help me with this problem?

Here's the instructions:
Write the first expression in terms of the second if the terminal point determined by t is in the given quadrant.

Problem:

sec^2(t)sin^2(t), cos (t) ; any quadrant

Thanks!
-Mark

Use the fact that sec(x) = 1/cos(x) and that sin^2(x) + cos^2(x) = 1.

if that's the case, would the answer be

sec^2 = 1/sqrt(1-sin^2)

Originally Posted by l flipboi l

Hello,

Can someone please help me with this problem?

Here's the instructions:
Write the first expression in terms of the second if the terminal point determined by t is in the given quadrant.

Problem:

sec^2(t)sin^2(t), cos (t) ; any quadrant

Thanks!
-Mark

Originally Posted by l flipboi l

if that's the case, would the answer be

sec^2 = 1/sqrt(1-sin^2)

Hi I flipboi l,

Using what Stapel told you....

Great!

I was wondering though, for the sec^2 (t) sin^2 (t)...why is there a sin^2 (t) there? what's it's purpose?

Originally Posted by l flipboi l

Great!

I was wondering though, for the sec^2 (t) sin^2 (t)...why is there a sin^2 (t) there? what's it's purpose?

I have no idea. Where did the expression originate? Is it an exercise in a textbook? Looks like this is an exercise in manipulating trigonometric expressions. Good practice, though.

Originally Posted by masters

I have no idea. Where did the expression originate? Is it an exercise in a textbook? Looks like this is an exercise in manipulating trigonometric expressions. Good practice, though.

yeah it came from the book. I'm trying to understand what sin^2(t) has to do with sec^2 (t) and why they're together.