how can i find the coordinates of the turning point at 4x(x-1)(x-2)?

this is my work to get the answer:

4x(x-1)(x-2)

=4x^3-12x^2+8x (divide 4)

=x^3-3x^2+2x

dy/dx=3x^2-6x+2=0

and how can i find the value of x??

please help me...

is that true my work to get the right answer?

can u teach me step by step?tq.