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Math Help - Expanding Log problem...

  1. #1
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    Expanding Log problem...

    Expand as the sum of individual logarithms, each of whose argument is linear: log(\frac{xy^2}{z^4})

    your help is appreciated! Thanks.
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  2. #2
    Super Member
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    Quote Originally Posted by Savior_Self View Post
    Expand as the sum of individual logarithms, each of whose argument is linear: log(\frac{xy^2}{z^4})

    your help is appreciated! Thanks.
    Using the following logarithm rules:

    log(ab) = log(a) + log(b)
    log(\frac{a}{b})= log(a) - log(b)
    log(a^n) = n \cdot log(a)

    I will start, see if you can finish:

    log(\frac{xy^2}{z^4}) = log(xy^2) - log(z^4) = log(xy^2) - 4log(z)

    ...
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  3. #3
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    Quote Originally Posted by Defunkt View Post
    Using the following logarithm rules:

    log(ab) = log(a) + log(b)
    log(\frac{a}{b})= log(a) - log(b)
    log(a^n) = n \cdot log(a)

    I will start, see if you can finish:

    log(\frac{xy^2}{z^4}) = log(xy^2) - log(z^4) = log(xy^2) - 4log(z)


    ...
    so...

    log(x) + log(y^2) - 4log(z)<br />
=<br />
log(x) + 2log(y) - 4log(z)

    answer being...

    log(x) + 2log(y) - 4log(z)

    Look good?
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  4. #4
    Super Member
    Joined
    Aug 2009
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    Israel
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    976
    Quote Originally Posted by Savior_Self View Post
    so...

    log(x) + log(y^2) - 4log(z)<br />
=<br />
log(x) + 2log(y) - 4log(z)

    answer being...

    log(x) + 2log(y) - 4log(z)

    Look good?
    Yes, that is correct.
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