Expand as the sum of individual logarithms, each of whose argument is linear: $\displaystyle log(\frac{xy^2}{z^4})$

your help is appreciated! Thanks.

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- Oct 13th 2009, 02:34 PMSavior_SelfExpanding Log problem...
Expand as the sum of individual logarithms, each of whose argument is linear: $\displaystyle log(\frac{xy^2}{z^4})$

your help is appreciated! Thanks. - Oct 13th 2009, 03:56 PMDefunkt
Using the following logarithm rules:

$\displaystyle log(ab) = log(a) + log(b)$

$\displaystyle log(\frac{a}{b})= log(a) - log(b)$

$\displaystyle log(a^n) = n \cdot log(a)$

I will start, see if you can finish:

$\displaystyle log(\frac{xy^2}{z^4}) = log(xy^2) - log(z^4) = log(xy^2) - 4log(z)$

... - Oct 13th 2009, 04:05 PMSavior_Self
- Oct 13th 2009, 04:50 PMDefunkt