Any help is greatly appreciated.

Thanks!

1. Solve the inequality and graph the solution on the real number line.

*x*3 +

3*x*2 –

9*x* –

27 ≤ 0

start by factoring the left side of the inequality using the grouping method
2. Find the critical numbers of the expression. (Enter your answers as a comma-separated list.)

3*x*3 –

32*x*2

set the expression equal to 0 and solve for x
3. Use the given zero to find all the zeros of the function. (Enter your answers as a comma-separated list. Include the given zero in your answer.)

*Function* *Zero* *f*(

*x*) =

*x*3 +

*x*2 +

4*x* +

4 2*i* if 2i is a root, then so is -2i ... the last root will be real. also note that f(x) will factor.

4. Find a polynomial function with real coefficients that has the given zeros. (There are many correct answers.)

4,

4*i*,

–4*i*
$\displaystyle \textcolor{blue}{f(x) = (x-r_1)(x-r_2)(x-r_3)}$

where each "r" is a zero
5. Use long division to divide. (

8*x*3 +

4*x*2 +

2*x* +

5) ÷ (2

*x*2 + 1)

it's kind of difficult to show long division in this venue

note this link ... Polynomial Long Division