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- Jan 28th 2007, 02:54 PM #1

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- Nov 2006
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## f(x)

Let f(x) = x^2 - 3x - 4.

a.) Find the slope, m(h), of the secant line between the points A(1, f(1)) and B(1 + h, f(1 + h)).

*Here's what I've come up with so far.

f(1) = 1^2 - 3(1) - 4

f(1) = -6

So, A is the point (1, -6)

f(1 + h) = (1 + h)^2 - 3(1 + h) - 4

f(1 + h) = 1 + 2h + h^2 - 3 - 3h - 4

f(1 + h) = h^2 - h - 6

So, B is the point (1 + h, h^2 - h - 6)

- Jan 28th 2007, 10:51 PM #2