$\displaystyle x^2+8x+11$

For standard form I got $\displaystyle (x+4)^2=5$ but I should have got

$\displaystyle (x-4)^2=-5$

according to the vertex formula:

-b/2a

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- Oct 12th 2009, 03:47 PMIsimbotWriting a function in standard form to find the vertex.
$\displaystyle x^2+8x+11$

For standard form I got $\displaystyle (x+4)^2=5$ but I should have got

$\displaystyle (x-4)^2=-5$

according to the vertex formula:

-b/2a - Oct 12th 2009, 03:59 PMmr fantastic