3^(7x-1) = 5^(3x+2)

I've tried to take the natural log of both sides, and pull x out of the exponent, but I can't seem to get the right answer.

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- Oct 12th 2009, 02:38 PMVelvet LoveSolving for X in both sides
3^(7x-1) = 5^(3x+2)

I've tried to take the natural log of both sides, and pull x out of the exponent, but I can't seem to get the right answer. - Oct 12th 2009, 02:42 PMVonNemo19
- Oct 12th 2009, 02:47 PMVelvet Love
That's what I've gotten it down to. Then I end up with ((ln(5)/ln(3))+3)/4, which is wrong. I'm rusty at pre-cal.

- Oct 12th 2009, 02:57 PMVonNemo19
- Oct 12th 2009, 03:12 PMVelvet Love
Thank you alot. That helped a lot. I'm glad I learn best by example :D

- Oct 15th 2009, 10:16 AMsanddollar
I worked out 1.51..... is that correct?

- Oct 15th 2009, 10:46 AMBabyMilo
- Oct 15th 2009, 11:32 AMstapel