http://i36.tinypic.com/24azvvo.jpg

That's the problem. I got an answer of -2 which I am not sure of. Help me please.

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- Oct 12th 2009, 10:40 AMThanasiSolve for x(problem includes fractions and imaginary)
http://i36.tinypic.com/24azvvo.jpg

That's the problem. I got an answer of -2 which I am not sure of. Help me please. - Oct 12th 2009, 10:48 AMe^(i*pi)
-2 does not lie in the domain of this function as it causes division by 0 on the RHS

$\displaystyle

\frac{1}{x-2} = \frac{3}{x+2} - \frac{6x}{(x-2)(x+2)}$

$\displaystyle

\frac{x+2}{(x+2)(x-2)} = \frac{3(x-2)}{(x-2)(x+2)} - \frac{6x}{(x-2)(x+2)}$

The denominator cancels

$\displaystyle x+2 = 3x-6-6x$

$\displaystyle x = -2$

That's unusual... - Oct 12th 2009, 10:48 AMearboth