600=25(17)^5x How would i rewrite this with logs? The 25 in front of (1.7)^5x threw me off so now I'm lost
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Originally Posted by midnightwynter 600=25(17)^5x How would i rewrite this with logs? The 25 in front of (1.7)^5x threw me off so now I'm lost $\displaystyle 600 = 25(1.7)^{5x}$ divide both sides by 25 ... $\displaystyle 24 = 1.7^{5x}$ can you finish?
thanks
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