600=25(1https://instruct.math.lsa.umich.edu/...144/char3A.png7)^5x
How would i rewrite this with logs?
The 25 in front of (1.7)^5x threw me off so now I'm lost
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600=25(1https://instruct.math.lsa.umich.edu/...144/char3A.png7)^5x
How would i rewrite this with logs?
The 25 in front of (1.7)^5x threw me off so now I'm lost
$\displaystyle 600 = 25(1.7)^{5x}$Quote:
Originally Posted by midnightwynter
divide both sides by 25 ...
$\displaystyle 24 = 1.7^{5x}$
can you finish?
thanks
