# Math Help - Solve for x

1. ## Solve for x

$log(2x+5) * log(9x^2) = 0$

Thanks a whole bunch!

2. Originally Posted by hydride
$log(2x+5) * log(9x^2) = 0$

Thanks a whole bunch!
either $2x+5 = 1$ or $9x^2 = 1$

3. Originally Posted by hydride
$log(2x+5) * log(9x^2) = 0$

Thanks a whole bunch!
I'll assume that the base of your logarithm is 10, however it doesn't really matter. In the case that [tex]log_{10}(2x+5)=0, we have $10^0=1=2x+5$. Just solve this equation for x. Do the same with the other factor.