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Math Help - I want check my answer and solve some question

  1. #1
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    I want check my answer and solve some question

    I want check my answer and solve some question

    Q :

    I want check my answer and solve some question-2222.jpg

    my answer from 33 - 38

    I want check my answer and solve some question-3333.jpg

    please help me in check this answer and solve questions from 39 to 42

    thanks
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  2. #2
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    Quote Originally Posted by r-soy View Post
    I want check my answer and solve some question

    Q :

    Click image for larger version. 

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    my answer from 33 - 38

    Click image for larger version. 

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    please help me in check this answer and solve questions from 39 to 42

    thanks
    You did correctly the questions #33, #34, #35

    The last 3 questions are wrong:
    #36: You used the wrong equation
    #37 no root to be used
    #38 use definition of absolute value and determine the appropriate domain
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  3. #3
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    Quote Originally Posted by earboth View Post
    You did correctly the questions #33, #34, #35

    The last 3 questions are wrong:
    #36: You used the wrong equation
    #37 no root to be used
    #38 use definition of absolute value and determine the appropriate domain
    thanks ,,,

    check it now

    I want check my answer and solve some question-55555.bmp

    earboth also i want solve questions from 39 to 42

    thanks >>
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  4. #4
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    Quote Originally Posted by r-soy View Post
    thanks ,,,

    check it now

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    earboth also i want solve questions from 39 to 42

    thanks >>
    1. #36 is wrong: You used the wrong equation
    2. #37 is OK now
    3. #38 is wrong. As I mentioned in my previous post you have to determine the appropriate domain. From

    x^3+|y|=6~\implies~|y|=6-x^3

    Since |y|\geq 0 you have to calculate those values for x that
    6-x^3\geq 0~\implies~x^3 \leq 6~\implies~\boxed{x\leq \sqrt[3]{6}}

    That means |y|=6-x^3\ ,\ x\leq \sqrt[3]{6} is a function.

    ...also i want solve questions from 39 to 42
    Definitely I won't do your homework. So show some work of your own and if there are some mistakes you'll get additional support.
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  5. #5
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    Now

    i try ::::
    I want check my answer and solve some question-www.jpg
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  6. #6
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    Quote Originally Posted by r-soy View Post
    Now

    i try ::::
    Click image for larger version. 

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    What you labeled #36 is actually #37. Usually an equation of a function starts with "y = ...". So your result is slightly unfinished (but correct)

    #39 is wrong.
    Explanation: \left(\dfrac0a = 0\ ,\ a \in \mathbb{R} \setminus \{0\}\right)

    #40 is OK

    #41 is wrong. You only have to solve the given equation for y to judge wether the equation describes a function or not.

    #42 is correct but incomplete. (Is this a function or not?)

    Initially you are asked to find the domain of those equations which define a function. The domains are missing
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  7. #7
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    you mean in #39 the equation of a function withou ( - ) or what ?
    what is wrong here ?

    #39
    <br />
\left(\dfrac0X = 0\ ,\ X \in \mathbb{R} \setminus \{0\}\right)<br />
function
    is ok now ?

    #41
    x + y = 1
    y = 1- x

    function

    #42 a function
    Last edited by r-soy; October 11th 2009 at 03:00 AM.
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  8. #8
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    Quote Originally Posted by r-soy View Post
    you mean in #39 no I meant #36 the equation of a function withou ( - ) or what ?
    what is wrong here ?

    #39
    <br />
\left(\dfrac0X = 0\ ,\ X \in \mathbb{R} \setminus \{0\}\right)<br />
function
    is ok now ? Unfortunately no:
    \color{blue}\bold{xy=0~\implies~y=0\ ,\ X \in \mathbb{R} \setminus \{0\}}

    #41
    x + y = 1
    y = 1- x
    function
    The transformations of the origianl equation is wrong:

    \color{blue}\bold{x^2+xy=1~\implies~xy=1-x^2~\implies~y=\dfrac1x-x\ ,\ x \in \mathbb{R} \setminus \{0\}}

    #42 a function <<<<< and what about the domain?
    In the 2nd sentence of the initial quaestion you are asked to find the domains of the functions. You haven't calculated a domain yet!
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  9. #9
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    For all that are NOT functions you are asked to "find a value of x top which there corresponds more than one value of y". You do not appear to have done that.
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  10. #10
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    Quote Originally Posted by HallsofIvy View Post
    For all that are NOT functions you are asked to "find a value of x top which there corresponds more than one value of y". You do not appear to have done that.

    thankz earboth
    HallsofIvy I did not understand it, can you please explain more
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  11. #11
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    ???
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  12. #12
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    Quote Originally Posted by HallsofIvy View Post
    For all that are NOT functions you are asked to "find a value of x top which there corresponds more than one value of y". You do not appear to have done that.
    what NOT functions ?
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  13. #13
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    Quote Originally Posted by r-soy View Post
    what NOT functions ?
    Please check your own notes: #34 and #35 are NOT functions. So you are asked to find at least one x-value with which you get at least 2 y-values.
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