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Math Help - Solve for x

  1. #1
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    Solve for x

    (8-3x)/(2*sqrt(4-x)) = 0

    How do you solve for x?
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  2. #2
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    Quote Originally Posted by Morgan82 View Post
    (8-3x)/(2*sqrt(4-x)) = 0

    How do you solve for x?
    \frac{8-3x}{2\sqrt{4-x}}=0

    A fraction can only equal zero if the numerator=0. Think about this. If the numerator is any other value, the fraction will have a value different from 0.

    Let \frac{p}{q}=0 and let's multiply both sides of the equation by q, which of course is allowed

    So q\cdot\frac{p}{q}=q\cdot 0

    So p=0

    This shows only the numerator must be 0

    So 8-3x=0

    Surely you can solve that

    One word of caution, you need to be sure that the value you get does not make the value of the denominator=0. For example, if you solve that and got x=2 (this is not the answer), then the denominator would be 0, which isn't allowed. We also can't have negative numbers under the radical, but actually 0 divided by a complex number is still zero, so we shall not worry about such circumstances for this problem
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