(8-3x)/(2*sqrt(4-x)) = 0
How do you solve for x?
$\displaystyle \frac{8-3x}{2\sqrt{4-x}}=0$
A fraction can only equal zero if the numerator=0. Think about this. If the numerator is any other value, the fraction will have a value different from 0.
Let $\displaystyle \frac{p}{q}=0$ and let's multiply both sides of the equation by q, which of course is allowed
So $\displaystyle q\cdot\frac{p}{q}=q\cdot 0$
So $\displaystyle p=0$
This shows only the numerator must be 0
So 8-3x=0
Surely you can solve that
One word of caution, you need to be sure that the value you get does not make the value of the denominator=0. For example, if you solve that and got x=2 (this is not the answer), then the denominator would be 0, which isn't allowed. We also can't have negative numbers under the radical, but actually 0 divided by a complex number is still zero, so we shall not worry about such circumstances for this problem