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**A Beautiful Mind** The problem is: $\displaystyle 4^x-2^{x+1}=3$

Here's the work I've tried doing on it:

$\displaystyle 4^x-2^{x+1}=3$

I split the $\displaystyle 2^{x+1}$ up into $\displaystyle -2^x+2^1$.

Then I...

$\displaystyle 4^x-2^x+2-3=0$

$\displaystyle 4^x-2^x -1= 0$

$\displaystyle 2^x-1=0$ me: (Different bases mean you can't take it away like that )

$\displaystyle Let 2^x = y.$

$\displaystyle y-1=0$

$\displaystyle y= 1$

$\displaystyle 2^x = 1$

$\displaystyle 2^0=1$

$\displaystyle x = 0$