x^2 - 50=0 (7.07)(7.07) - 50 =0 Is this the correct way to write out a quadratic equation like that?
Follow Math Help Forum on Facebook and Google+
Originally Posted by wolfhound x^2 - 50=0 (7.07)(7.07) - 50 =0 Is this the correct way to write out a quadratic equation like that? $\displaystyle x^2-50=0$ This is a quadratic equation I assume that you want to solve for x $\displaystyle x^2=50$ $\displaystyle x=\pm 7.07 $ Is that what you want to know ?
Are you supposed to use decimal approximations, instead of the exact answers?
View Tag Cloud