x^2 - 50=0 (7.07)(7.07) - 50 =0 Is this the correct way to write out a quadratic equation like that?
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Originally Posted by wolfhound x^2 - 50=0 (7.07)(7.07) - 50 =0 Is this the correct way to write out a quadratic equation like that? This is a quadratic equation I assume that you want to solve for x Is that what you want to know ?
Are you supposed to use decimal approximations, instead of the exact answers?
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