6x^2 - x - 2=0 6x^2 -4x +3x -2=0 2x(3x-2)1(3x-2)=0 (2x+1)=0 2x=-1 ,x=-1/2 3x-2=0,x=-2/3 I cant understand where I went wrong on this the answer is supposed to be x=-1.33 and x=1
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If x = 1, then 6x^2 - x - 2 = 6(1)^2 - (1) - 2 = 6 - 1 - 3 = 3, not zero. Either the book has a typo, or maybe you looked at the solution to the wrong exercise...?
Originally Posted by wolfhound 6x^2 - x - 2=0 6x^2 -4x +3x -2=0 2x(3x-2)1(3x-2)=0 (2x+1)=0 2x=-1 ,x=-1/2 3x-2=0,x=-2/3 I cant understand where I went wrong on this the answer is supposed to be x=-1.33 and x=1 (2x+1)(3x-2)=0 x=-1/2 , x=2/3 the answer is wrong .
Originally Posted by stapel If x = 1, then 6x^2 - x - 2 = 6(1)^2 - (1) - 2 = 6 - 1 - 3 = 3, not zero. Either the book has a typo, or maybe you looked at the solution to the wrong exercise...? Sorry I mean x=-1.33 and x=1 as the final answers I didnt mean x=1 as the initial value!?
Originally Posted by mathaddict (2x+1)(3x-2)=0 x=-1/2 , x=2/3 the answer is wrong . I know its Wrong! That why I have asked for help here????
Originally Posted by wolfhound I know its Wrong! That why I have asked for help here???? i mean the answer of the book is wrong , not yours but of course yours is wrong too .
Originally Posted by mathaddict i mean the answer of the book is wrong , not yours but of course yours is wrong too . If mine is wrong then what is the correct way of doing it?
Originally Posted by wolfhound If mine is wrong then what is the correct way of doing it? I just posted the correct answers . Well , you are almost correct but you added a negative sign to one of the roots . Refer back to my post .
Originally Posted by mathaddict I just posted the correct answers . Well , you are almost correct but you added a negative sign to one of the roots . Refer back to my post . could you tell me how change the fractions into decimal numbers please?
Originally Posted by wolfhound 6x^2 - x - 2=0 6x^2 -4x +3x -2=0 2x(3x-2)+(3x-2)=0 <<<<<< here you made a tiny but very effective typo (2x+1)=0 2x=-1 ,x=-1/2 3x-2=0,x=-2/3 I cant understand where I went wrong on this the answer is supposed to be x=-1.33 and x=1 $\displaystyle 6x^2 -4x +3x -2=0~\implies~2x(3x-2)+(3x-2)=0~\implies~(3x-2)(2x+1)=0$ and so on ...
Originally Posted by earboth $\displaystyle 6x^2 -4x +3x -2=0~\implies~2x(3x-2)+(3x-2)=0~\implies~(3x-2)(2x+1)=0$ and so on ... thanks could you tell me if x=1/2 or x=2/3 is the correct answer?? and how could I change these out of fractions please?
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