find the limits:
3. F(x)= (e^x+e^-x)/e^x+1
4. f(x)=2x/x-3 ln x/3 x=3
5. f(x)=e^[(2-x)/x] x=5 (x goes to 5)
any help is appreciated. thanx
3. divide top and bottom by $\displaystyle e^x$ and let x go to infinity (if thats the limit being asked) bearing in mind $\displaystyle e^{-x}=\frac{1}{e^x}=0$ in the limit x goes to infinity
5. just plug x=5 into the equation
What you have written for 3 makes no sense. In order to talk about a "limit" you must have a limit as x goes to some valule. Krahl assumed you were talking about the limit as x goes to infinity. Is that correct?
For both 4 and 5, just plug the number into the formula.