
Describing end behavior
f(x) = (3x)/(x^216)
Describe the behavior of f(x) to the left and right of each asymptote.
Asymptotes are y= 4 and y= 4
The right behavior of the first asymptote at y = 4 is ∞correct? Would the left behavior at asymptote then be  ∞?
And the right behavior of the asymptote y = 4 would also be ∞ and the left would again be ∞?
Would someone mind correcting this if necessary?
http://www.walterzorn.com/grapher/grapher_e.htm here is a grapher if you need.
Thanks so much!

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murphie, this graph may help you visualize the graph .. . .
(Rock)

I'm confused, the graph from my calculator looks completely different, your graph suggests that the left behavior at y=4 is  infinity, and  infinity on the right?? and for the asymptote at y=4 the left is  infinity and right is infinity?
I am fairly bad at calculus so feel free to correct me if i said something stupid. But thanks for your help.

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your equation can be rearranged into this,
y = (3  x)/((x  4)(x + 4)), that means x = 4 and x = 4 are vertical asymptotes.
y approaches zero as x approaches positive or negative infinity