Results 1 to 3 of 3

Math Help - Limit- Evaluation

  1. #1
    Junior Member
    Joined
    Nov 2006
    Posts
    38

    Limit- Evaluation

    Hi there..

    can someone help me determine that limit for the following function, as x --> -2?

    Follow Math Help Forum on Facebook and Google+

  2. #2
    Rhymes with Orange Chris L T521's Avatar
    Joined
    May 2008
    From
    Santa Cruz, CA
    Posts
    2,844
    Thanks
    3
    Quote Originally Posted by ty2391 View Post
    Hi there..

    can someone help me determine that limit for the following function, as x --> -2?

    Note that \left|x\right|=\left\{\begin{array}{rl} x, & \text{ if } x\geq0\\ {\color{red}-x}, & \text{ if } x<0\end{array}\right.

    So \lim_{x\to-2}\frac{2-\left|x\right|}{2+x}=\lim_{x\to-2}\frac{2-(-x)}{2+x}=\lim_{x\to-2}\frac{2+x}{2+x}=1

    Does this make sense?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    Nov 2006
    Posts
    38
    That makes sense. However, do you not have to evaluate the left and right hand limits and equate them to prove that the limit exists? In that case, how would you evaluate the right hand limit?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Evaluation of limit (2)
    Posted in the Calculus Forum
    Replies: 10
    Last Post: October 10th 2011, 03:15 AM
  2. Evaluation of limit.
    Posted in the Calculus Forum
    Replies: 6
    Last Post: October 9th 2011, 09:48 AM
  3. [SOLVED] Limit evaluation
    Posted in the Calculus Forum
    Replies: 4
    Last Post: November 28th 2010, 01:24 PM
  4. Limit evaluation
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: October 14th 2009, 04:36 AM
  5. [SOLVED] Evaluation of a limit
    Posted in the Calculus Forum
    Replies: 1
    Last Post: February 24th 2009, 01:14 PM

Search Tags


/mathhelpforum @mathhelpforum