$\displaystyle P(x)=3x^4-kx^3+7x^2-x+1 $ If $\displaystyle P(x)=Q(x) [x-3]+W$ determine $\displaystyle Q(x) $ and $\displaystyle W $
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Originally Posted by Coukapecker $\displaystyle P(x)=3x^4-kx^3+7x^2-x+1 $ If $\displaystyle P(x)=Q(x) [x-3]+W$ determine $\displaystyle Q(x) $ and $\displaystyle W $ W = P(3) (why?). To get Q(x), I suggest you do a polynomial long division. That is, divide x - 3 into P(X). This will also confirm the value of W.
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